There is another way. In this configuration, the FETs are being used as "ideal" diodes.
If the battery is connected properly, the FET will turn on. In reverse, the FETs stay off and nothing blows up.
The problem here is the FETs have to handle the full load current, so you may need many in parallel to keep the heat down. Using a very low on resistance FET helps too. I usually estimate about 20 amps per IRFB4110 with no heat sink. With a heat sink, they can handle a lot more. But we don't want it to get hot. You could use about any N channel Mosfet, but do the math on the heat dissipation.
The gate drive resistors will drain about 1uA per volt of pack voltage, so not a big deal. As shown, a minimum of 24v is needed on the pack. For lower voltages, R1 would need to be reduced.

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