dnmun
1 PW
i just read this thread for the first time.
does anyone understand that the three 1500R resistors in parallel are there to reduce the voltage input to the voltage regulator? they have nothing to do with setting the LVC.
for a generic processor, expect the pin on the microprocessor that gets the LVC voltage to be #1 or #2 in the upper left. it may be different on some.
but you want to find the resistor divider bridge between Vcc and ground which has a trace coming out from the middle of the divider and running up to the micro. that's why looking at those pins on the micro can help you find the bridge.
if it is a 72V controller on the label then it will have a 60V LVC since they are all set up to use SLA.
if you need to reduce the LVC then find the resistor in the divider bridge between the trace that goes to the micro on one side and to ground on the other side.
if you have a 16S lifepo4 pack, then the LVC can be set as low as about 35V.
so you would want the new resistor below the trace to be 35/60 of the original. so about 7/12 the original value. so if the resistor is now 1k ohm, you can solder another surface mount resistor right on top of the old one so the new equivalent resistance is 7/12 of the old value and you would then have a 35V LVC. no cutting or drilling or anything insane. just add a new resistor in parallel with the old and of a value such that the equivalent resistance of the two in parallel will get you to the new LVC you want.
for example. current resistor 1kR, you wanna go from 60V LVC to 54V for 20S lipo. 54/60=.9
so the equivalent resistance will be .9 R1 where R1 is the original resistor. add R2 in parallel and solve
.9R1=(R1xR2)/(R1+R2) solve for R2
can anyone do that?
if you can solve that, then you can simply add another resistor in parallel. if not then buy another controller of the LVC you need.
ps: it actually is more complicated than this, in that you really have to add the in the value of the resistors in the divider network above the trace to the micro and use that to find the ratio of the lower resistor to the total resistance and then change that ratio by the amount needed. but those resistors above are much larger values so the ratio is essentially the same. so this is a simple way to solve for the new LVC without too much math.
does anyone understand that the three 1500R resistors in parallel are there to reduce the voltage input to the voltage regulator? they have nothing to do with setting the LVC.
for a generic processor, expect the pin on the microprocessor that gets the LVC voltage to be #1 or #2 in the upper left. it may be different on some.
but you want to find the resistor divider bridge between Vcc and ground which has a trace coming out from the middle of the divider and running up to the micro. that's why looking at those pins on the micro can help you find the bridge.
if it is a 72V controller on the label then it will have a 60V LVC since they are all set up to use SLA.
if you need to reduce the LVC then find the resistor in the divider bridge between the trace that goes to the micro on one side and to ground on the other side.
if you have a 16S lifepo4 pack, then the LVC can be set as low as about 35V.
so you would want the new resistor below the trace to be 35/60 of the original. so about 7/12 the original value. so if the resistor is now 1k ohm, you can solder another surface mount resistor right on top of the old one so the new equivalent resistance is 7/12 of the old value and you would then have a 35V LVC. no cutting or drilling or anything insane. just add a new resistor in parallel with the old and of a value such that the equivalent resistance of the two in parallel will get you to the new LVC you want.
for example. current resistor 1kR, you wanna go from 60V LVC to 54V for 20S lipo. 54/60=.9
so the equivalent resistance will be .9 R1 where R1 is the original resistor. add R2 in parallel and solve
.9R1=(R1xR2)/(R1+R2) solve for R2
can anyone do that?
if you can solve that, then you can simply add another resistor in parallel. if not then buy another controller of the LVC you need.
ps: it actually is more complicated than this, in that you really have to add the in the value of the resistors in the divider network above the trace to the micro and use that to find the ratio of the lower resistor to the total resistance and then change that ratio by the amount needed. but those resistors above are much larger values so the ratio is essentially the same. so this is a simple way to solve for the new LVC without too much math.