I was thinking of using an Allegro 150A current sensor (instead of a shunt) for measuring current in a circuit.
The rated resistance of the component is 100uOhm (I guess it's milliohms).
How can I know how many watts can it dissipate?
It should measure up to 120V and up to 150A so how can I know the power dissipation and potential heat considering all of these numbers?
Also, how low is 100uOhm compared to the resistance of those big metal shunts?
Also, same question about this linear step down regulator:
http://www.analog.com/media/en/technical-documentation/data-sheets/7138f.pdf
At 120V and lets say 300mA of circuit power consumption, how hot can it get? I was told that if the circuit draws 5V it would need to dissipate 115V at 0.3A which is like 34W through that tiny component.
If thats true then it seems phisically impossible and if thats the case then how come it's rated for 140V and 400mA?
The rated resistance of the component is 100uOhm (I guess it's milliohms).
How can I know how many watts can it dissipate?
It should measure up to 120V and up to 150A so how can I know the power dissipation and potential heat considering all of these numbers?
Also, how low is 100uOhm compared to the resistance of those big metal shunts?
Also, same question about this linear step down regulator:
http://www.analog.com/media/en/technical-documentation/data-sheets/7138f.pdf
At 120V and lets say 300mA of circuit power consumption, how hot can it get? I was told that if the circuit draws 5V it would need to dissipate 115V at 0.3A which is like 34W through that tiny component.
If thats true then it seems phisically impossible and if thats the case then how come it's rated for 140V and 400mA?