I have the data sheet(pdf) for some Kemtron conductive foam.
The specs give two figures for the foams resistivity:
Surface resistivity: 0.05Ω/sq
Volume resistivity: 0.015Ω/sq
I was trying to work out what energy would be consumed if this was used to connect to a 18650 battery, but the units; Ω/sq, is something I've never encountered before; and the wikipedia article doesn't clarify things much.
To turn this into an example to which I might understand the answer, if I draw say 5A at 3.7 volts through a pad of 1.5mm thick conductive foam attached to the 254mm^2 base of the cell; how much energy will be lost to heating the foam?
Thanks for any insights you can give me.
The specs give two figures for the foams resistivity:
Surface resistivity: 0.05Ω/sq
Volume resistivity: 0.015Ω/sq
I was trying to work out what energy would be consumed if this was used to connect to a 18650 battery, but the units; Ω/sq, is something I've never encountered before; and the wikipedia article doesn't clarify things much.
To turn this into an example to which I might understand the answer, if I draw say 5A at 3.7 volts through a pad of 1.5mm thick conductive foam attached to the 254mm^2 base of the cell; how much energy will be lost to heating the foam?
Thanks for any insights you can give me.