A Dual Motor Tandem Bicycle
I posted on the MXUS 3000 Hub Motor
asking about this. Fastest average speeds will need to be only in the 50-60 mile range, to accommodate the local roads & road laws. That makes 6000 watts of power enough for this race. There is some optimum amount of battery, hence weight, also more charging time, motive power compromise - a design conundrum
See notes on How to Solar Charge an Electric Bicycle
. This tandem bicycle would be a variation of the solar eBike camping trip, albeit very long. Camping cuts down the amount of time spent on the sleep cycle. Light weight solar pv that can be carried un-furled.
Given the rather droll set of rules emerging, that an electric vehicle can plug in anywhere, and vehicle swapping or battery swapping, I'm not particularly interested in this race. It does obviate my interest in the design challenge posed, or in some world-wide cooperative competitions fielding a vehicle which would allow around the globe fast racing on ambient energy alone (wind & solar). My rules would be only one vehicle only (no swapping either of vehicle or battery) and that its charging capability be on-board and all charging use its carried source.
So that would be challenging, for designer, builders and racing drivers.
So let's say a tandem dual-motor eBike built on the basis of two MXUS 3000 motors. They are direct drive. Meaning forward & reverse, regenerative braking and spinning backwards, capable of charging up your batteries. The problem then becomes how to do that and wind is the best answer.
So I ask, what is the blade length needed to spin the MXUS 3000 for charge? See Wind Speed and Power
Obviously a lot of variation in wind speed. The aim would be to carry both light weigh solar PV and the blades to turn the bicycle wheels into wind turbines. Theoretical, and latter we'll worry about how to rig such a thing in way that it could all be carried on the bicycle. Think tandem bicycle, so that could be longer than optimum for a ride, just to carry a set of 3 blades - length does matter except to optimize the spin on the MXUS.
As a mathematical exercise, I'll look at my locality. The generalize that over a broader area.
from: https://weatherspark.com/averages/31162 ... ted-States
For simplicity sake, I'll take a 10mph average. So A is 3000/(0.0052 * 1000) = 577 sq.ft. A = (pi) r-squared. So the rotor blade would need to be 13.5 feet. At least within some measure of feasibility. Next we'll calculate battery size and necessary charging characteristics optimizing the design a bit more.