Kingfish
100 MW
EDIT: Appending TOC.
Math Modeling
Greetings –
I am working through some equations however I need some other eyes to cross-check my math; it’s difficult at times to work solo in cave…
Equation:
Power (watts) = Torque(Nm) x Angular Velocity(rads/sec), or
Example Problem:
Solve for theoretical value of Torque when a 24†wheel is using 2 hp to spin at 30 mph.
Rearranging the equation from above, Ä = P/É
Therefore…
24-inch tire = 2 foot diameter (d).
Circumference of 2-foot tire = À d -> À * 2 = 6.283 feet (per revolution)
If 1 mile = 5280 feet, 30 miles = 30 * 5280 = 158400 feet.
With 1 hour = 60 minutes,
rpm = (158400 feet / 6.283 feet) / 60 = 420.2
É = (2 À *rpm)/60 -> (2 À * 420.2) / 60 = 44 rads/s.
If 1 hp = 745.7 watts then P = 2 * 746 watts = 1491.4 w
Resolving Ä = P/É -> Ä = 1491.4/44 = 33.9 Nm
The problem I have is A) do I have the math correct, and B) that my unit conversions are correct.
Thanks, KF
- Math Modeling
- Axial Flux Design, Halbach, Ironless-Stator, Axial Motor
- Axial Flux Design, Non-Halbach, Ironless-Stator, Axial Motor
Math Modeling
Greetings –
I am working through some equations however I need some other eyes to cross-check my math; it’s difficult at times to work solo in cave…
Equation:
Power (watts) = Torque(Nm) x Angular Velocity(rads/sec), or
- P = Ä * É
-
Where...
É = (2 À *rpm)/60 = rads/s
Example Problem:
Solve for theoretical value of Torque when a 24†wheel is using 2 hp to spin at 30 mph.
Rearranging the equation from above, Ä = P/É
Therefore…
24-inch tire = 2 foot diameter (d).
Circumference of 2-foot tire = À d -> À * 2 = 6.283 feet (per revolution)
If 1 mile = 5280 feet, 30 miles = 30 * 5280 = 158400 feet.
With 1 hour = 60 minutes,
rpm = (158400 feet / 6.283 feet) / 60 = 420.2
É = (2 À *rpm)/60 -> (2 À * 420.2) / 60 = 44 rads/s.
If 1 hp = 745.7 watts then P = 2 * 746 watts = 1491.4 w
Resolving Ä = P/É -> Ä = 1491.4/44 = 33.9 Nm
The problem I have is A) do I have the math correct, and B) that my unit conversions are correct.
Thanks, KF