Chalo
100 TW
Why back EMF is unwanted is the mystery to me. It serves to limit a motor's speed and allows careful setup to let the motor operate within its most efficient RPM range.
Punx0r said:Nothing in there explains this first paragraph which is unusual and does deserve an explanation. I can only guess it's something to do with the unpowered phase as the motor rotates, but it's open-circuit
Punx0r said:certainly not at EMF is a magnetic field or current (come on, that one jumped out even to me).
Punx0r said:It doesn't seem to support anything you're claiming,
kdog said:tone down the mud slinging dude
major said:This BEMF is NOT the generated voltage arising from the motion of the coils in the field.
Browser said:major said:This BEMF is NOT the generated voltage arising from the motion of the coils in the field.
And you are still wrong! And still trying to change physics.
The relative motion of the coils and magnets is exact cause back-EMF in motors.
The applied voltage causes the movement. Whenever you have coils moving through magnetic fields, a voltage is induced that (by Lenz) opposes that motion. That is the back-EMF in motors.
major said:In armatures for most all motors and generators, the armature current, or more precisely, the coil currents must be time varying or switched. This does give rise to BEMF due to the coil inductance. This BEMF is NOT the generated voltage arising from the motion of the coils in the field. These are two different phenomena.
More precisely, the induced (or generated) voltage, per Faraday with the negative sign per Lenz, will, if allowed to, produce a current which will cause a force (or torque) to oppose the motion (or rotation). If this applied voltage is greater than the generated voltage, then current will flow in the direction to created a torque which will aid rotation and it is a motor, converting electric to mechanical power. Per Lenz, the generated voltage opposes the applied voltage. The magnitude of power converted is the armature current times the generated voltage. The applied voltage is the sum of the voltage drop across the armature impedance and the generated voltage.Browser said:The applied voltage causes the movement. Whenever you have coils moving through magnetic fields, a voltage is induced that (by Lenz) opposes that motion. That is the back-EMF in motors.
Browser said:My original question was (I thought) relatively clear: Why don't people use solid conductors? Why (what criteria) cause some people to use fewer turns of thicker wire vs more turns of thinner wire (assuming equal total area)?
Browser said:From the limited amount of information I've been able to find about the use of foil-wound coils -- they seem to see most use in high-voltage, AC transformers and radio frequency inductors -- a part of the reason for their use -- besides that they are easier/cheaper to wind for very large coild use in HV transformers -- is that they are less susceptible to AC eddy current induction.
major said:I think that demonstrates that it is different from the BEMF due to the coil inductance.
major said:If one rotates the field in the armature and has the armature connections open circuit then no armature (coil) current can flow, so the L*di/dt component must be zero. Yet there is the voltage (generated voltage) across the armature connections. The generated voltage is there regardless of the current. I think that demonstrates that it is different from the BEMF due to the coil inductance.... Put a voltmeter or scope on a motor armature connections and spin it. You see the generated voltage. There is essentially zero current because the instruments are so high impedance, so there is no BEMF due to inductance in the motor.
(the)Faraday said:A changing magnetic flux impinging on a conductor creates an electric field and hence a current (eddy current*)
Browser said:major said:So I am saying that the BEMF from the changing current and the coil inductance is separate and different from the generated voltage caused by the motion of the coil in the magnetic field of the motor. You disagree. A voltage (BEMF) caused by changing current and inductance is quantified L*di/dt. The voltage due to the motion in the field is per Faraday's Law, -N*dΦ/dt. If one rotates the field in the armature and has the armature connections open circuit then no armature (coil) current can flow, so the L*di/dt component must be zero. Yet there is the voltage (generated voltage) across the armature connections. The generated voltage is there regardless of the current. I think that demonstrates that it is different from the BEMF due to the coil inductance. It is different.
You think; I know you're wrong. I'm stating physics and you are making it up as you go along.
Back there, I quoted two, authoritative sources speaking about the ....
Punx0r said:However, the standard line is that neither the PWM nor commutation frequency of a typical motor is anywhere near high enough to worry about skin effect.
major said:How's this for authoritative?
Introducing Faraday's Law
L. L. Tankersley and Eugene P. Mosca
Physics Department
United States Naval Academy
Annapolis, MD 21402
major said:But that reference appears to support my contention.
Browser said:major said:How's this for authoritative?
Introducing Faraday's Law
L. L. Tankersley and Eugene P. Mosca
Physics Department
United States Naval Academy
Annapolis, MD 21402
Fine as a source.
major said:But that reference appears to support my contention.
Appears to you to support your contention.
But that image, drawn from an unlinked source, that happens to mention "two different phenomena" and magnetism, but no mention of backEMF or eddy currents, with most of the references not shown and no context, you might just as well have scribbled the three words on your wall in crayon and posted a pic of it.
Did you read the document I linked? Did you make it to page 84 entitled "Eddy Currents Increase Winding Loss" with the explanation and formulae and worked examples?
No. You went a looked for a discombobulated image that "appears to support your contention"; if you squint your eyes a bit, ignore all the missing information and forget the history of your posts in this thread.
Yeah, right!
Browser said:If you are on a hill and the motor is supplying just enough torque to stop you rolling back, but not enough to allow you to move forward, IT IS STILL DOING WORK!
Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force
From: http://www.britannica.com/science/work-physicsNo work, as understood in this context, is done unless the object is displaced in some way and there is a component of the force along the path over which the object is moved. Holding a heavy object stationary does not transfer energy to it, because there is no displacement.
I don't think you can do it; find people who know more than you.Browser said:So, I'm off to pastures new to find people,...., who know more than me,
major said:I'm saying that eddy currents do not enter into Faraday's Law
Eddy currents (also called Foucault currents[1]) are loops of electric current induced within conductors by a changing magnetic field in the conductor, due to Faraday's law of induction
and underConductors (of finite dimensions) moving through a uniform magnetic field, or stationary within a changing magnetic field, will have currents induced within them. These induced eddy currents can be undesirable, since they dissipate energy in the resistance of the conductor.
In this illustration, a solid copper bar inductor on a rotating armature is just passing under the tip of the pole piece N of the field magnet. Note the uneven distribution of the lines of force across the bar inductor. The magnetic field is more concentrated and thus stronger on the left edge of the copper bar (a,b) while the field is weaker on the right edge (c,d). Since the two edges of the bar move with the same velocity, this difference in field strength across the bar creates whorls or current eddies within the copper bar.[23]![]()
High current power-frequency devices, such as electric motors, generators and transformers, use multiple small conductors in parallel to break up the eddy flows that can form within large solid conductors.
https://www.youtube.com/watch?v=OIcZRSBTTY010. Faraday's Law - MIT
If a solid conductor were used instead of
a loop, as shown in Figure 10.5.1, current can also be induced. The induced current
appears to be circulating and is called an eddy current.
https://www.boundless.com/physics/t...-eddy-currents-and-magnetic-damping-571-8079/Induced EMF - Faraday's Law, Lenz's Law & Eddy Currents
http://www.phy.davidson.edu/FacHome/wbh/PHY220Lectures/21.3-21.5.pdfBack EMF, eddy currents, and magnetic damping are all due to induced EMF and can be explained by Faraday's law of induction.
http://www.electronics-tutorials.ws/electromagnetism/electromagnetic-induction.htmlCirculating currents (eddy currents) are induced in bulk conductors moving through a magnetic field
http://hsc.csu.edu.au/physics/core/motors/2606/PHY932net.htmlBut a changing magnetic flux produces a varying current through the coil which itself will produce its own magnetic field as we saw in the Electromagnets tutorial. This self-induced emf opposes the change that is causing it and the faster the rate of change of current the greater is the opposing emf. This self-induced emf will, by Lenz’s law oppose the change in current in the coil and because of its direction this self-induced emf is generally called a back-emf.
explain that, in electric motors, back emf opposes the supply emf
Back emf is the emf induced in the coils of a motor as they spin in the external magnetic field of the stator.
By Lenz's law the direction of that induced emf opposes the emf causing the motion of the armature. The current generated in the motor is an eddy current. The direction of the motor eddy current is such that it opposes the supply emf that produces the motion in the motor. The net emf applied to the coils equals the supply emf minus the back emf.
The back emf increases as the speed of the motor increases, until the net emf is just sufficient to provide the energy for the work the motor is doing, against its own internal friction and any load that is applied to it. If there were no back emf, the motor would continue to spin faster and faster indefinitely.
When a greater load is applied to the motor, the armature rotates more slowly and the back emf is reduced. This allows a greater current to flow through the coils, resulting in an increased torque to match the extra load.
At low speeds, when the back emf is small, the motor coils are protected by a series resistor from the large currents that could flow and burn out the motor. This resistor is switched out at higher speeds when the back emf replaces the role played by the resistor at low speed.
major said:Browser said:If you are on a hill and the motor is supplying just enough torque to stop you rolling back, but not enough to allow you to move forward, IT IS STILL DOING WORK!
Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external forceNo work, as understood in this context, is done unless the object is displaced in some way and there is a component of the force along the path over which the object is moved. Holding a heavy object stationary does not transfer energy to it, because there is no displacement.
Chalo said:So you're talking superficially understood theory with a bunch of guys who have a lot of practical experience under their belts? Good luck with that.
Chalo said:My suggestion is to understand why conventional practice is conventional, then question it. Until you complete step one, step two accomplishes nothing.
Browser said:But, my motor has 36 poles and is intended to run at 20,000rpm. So, 36 * 20e3 * 10 = 120kHz.
The skin depth of copper at that frequency (at 100C) is sqrt( 2 / 2 * pi * 120e3 * 4 * pi * 1e-7 * 5.98e7 ) = 1.8787e-4 = 0.18787 mm. I do need to worry about it.
That's why I'm looking at 0.1mm Cu foil with 0.025 polyester insulation between turns.
Browser said:If you are on a hill and the motor is supplying just enough torque to stop you rolling back, but not enough to allow you to move forward, IT IS STILL DOING WORK!
(Please!) Get someone to take you in their car to a hill. Have them park on that hill. You get out, go round to the downhill end of that car and brace yourself against it. Have them let off the handbrake (parking brake in the US).
Now tell me that you do not expend any energy -- THAT YOU DO NO WORK -- preventing the car from rolling down hill and squashing you.
Chalo said:I suggest that a lifelong pro baker can make better bread than a young microbiologist specializing in yeast.
The same principle applies to motors.