number1cruncher said:
I assume there must be extra components between the bridge and AC receptacles. Should you just look for the diode/BR closest to the input? I smoked a 12V 1A ps the other day by just hooking up to the AC inputs. It was just an old 750MB Iomega Zip Drive ps, so no big deal. Actually got another one I'll try your suggestion on. :wink: Thanks!
First, make sure it is not a transformer-based wallwart. If what you see inside is a bridge, a cap, a single large transformer, then you can't use that kind on DC. It *will* smoke when you hook up DC to it if the windings aren't capable of the current load, because it will just flow current steadily thru it like a long piece of wire. The transformer comes first electrically, so right off the AC input prongs.
If it's a switched supply (usable for DC-DC operation), it will have first a bridge, then caps, then some switching electronics like transistor, MOSFET, or IGBT, then small transformer, then some more electronics like TO220-style diode packs/etc, more caps, sometimes another transformer or inductor that looks like one, etc. Often lots of little parts around it and maybe an IC for control, sometimes more than one.
If the SMPS type uses a fullwave bridge (the only type you'd have to worry about) there will either be a bridge module or four diodes on the board before the main input cap(s) but after the AC input wires. They will be wired up so two have their striped ends connected, the other two have their non-striped ends connected, and the two sets will be connected at their opposing ends stripe-to-non-stripe. You just need to move the input to the points where the two stripes connect (for -) and where the two non-stripes connect (for +).
If it's a bridge module, it'll have four pins, two with ~ marks and two with + / -. Just hook in your DC input to the + / -.
If there is only two input diodes, it's a half-bridge, and will only pass current one-way anyway, so doesn't matter if you bypass it or not. The only advantage to bypassing it is that you get about 1.4V less drop on the input, thus that much more ability to put out power from the adapter as a whole.