DrkAngel
1 GW
Simplest - most basic, explanation of how a brushless motor works.
Power is regulated by modulating the amperage applied to the motor, by the controller.
(Typically, in a regulated, 3 phase arrangement. )
This is done via a series of full voltage pulses, the width, and quantity of which, determines the power input, (amps x battery voltage).
Additional amps supplied, increases motor "torque", but does not affect the "unloaded" ** top speed.
Amperage application is limited by controller capacity - or as a function of thermal depreciation.
(Thermal resistance of wire increases, as its temperature rises.
The application of more amps, shifts efficiency lower, as heat to torque ratio, increases.)
200% amp input might increase output to 150%. (Which Increases watt output, also.)
Additional, speed, as well as rated motor output - "watts", is obtained via the increase of supplied voltage.
Ex. Upgrading from 24v to 36v will enhance output, from 500w to 750w, which raises the torque curve, as well as increases the top "unloaded" ** speed by a full 50%.
Note: The "output" or "motor rated", "watts" is a fraction of the input "watts".
1000w input might produce a, usable, 750w output, = 3/4 = 75% efficiency rate.
** "Unloaded speed", is specified, to avoid, having to, explain-factor in, wind resistance, road load, component resistance etc., which are significant, measurable, factors during actual usage.
Please Note: I'm trying to keep this as simple-basic-understandable as possible!
Subject to enhancement ...
Power is regulated by modulating the amperage applied to the motor, by the controller.
(Typically, in a regulated, 3 phase arrangement. )
This is done via a series of full voltage pulses, the width, and quantity of which, determines the power input, (amps x battery voltage).
Additional amps supplied, increases motor "torque", but does not affect the "unloaded" ** top speed.
Amperage application is limited by controller capacity - or as a function of thermal depreciation.
(Thermal resistance of wire increases, as its temperature rises.
The application of more amps, shifts efficiency lower, as heat to torque ratio, increases.)
200% amp input might increase output to 150%. (Which Increases watt output, also.)
Additional, speed, as well as rated motor output - "watts", is obtained via the increase of supplied voltage.
Ex. Upgrading from 24v to 36v will enhance output, from 500w to 750w, which raises the torque curve, as well as increases the top "unloaded" ** speed by a full 50%.
Note: The "output" or "motor rated", "watts" is a fraction of the input "watts".
1000w input might produce a, usable, 750w output, = 3/4 = 75% efficiency rate.
** "Unloaded speed", is specified, to avoid, having to, explain-factor in, wind resistance, road load, component resistance etc., which are significant, measurable, factors during actual usage.
Please Note: I'm trying to keep this as simple-basic-understandable as possible!
Subject to enhancement ...