How big would a mirror be that is 1 foot long have to be melt 132grams of ice to water, from 0°C to 1°C, deltaT, in 6mintutes? 7363.83joules per minute, I don't think I want joule seconds. 122j/s?
What if I call the solar potential for 1m^2 is 145w at sea level? And the mirror casts a 1m^2 shadow on the ground. It is 90% efficient at reflecting and applies 130.5w. I think a square meter mirror could melt 132g of ice in 6 minutes. Then, how much air do I have to flow through it to refreeze the 132g? It would depend on the temperature of the air in my compressor. If I use an electric two stage compressor head the temperature of the air will be lower after it goes through the compressor. So, if it is 0 degrees it might be -1degrees. When I am designing isothermal generators, I often use the two stage air compressor head outside of an ice chest, while the air cylinder for that compressor head is inside of the ice chest. I use the ice chest to keep my compressed air at 0 degrees, or whatever the optimum temperature is for the generator.
V = π(R² - r²)h
3.14(0.5" - 0.1875)12
8.095cubic inches of water if I make a 1" pex tube with a 3/8" copper tube one foot long.
132.65mm per foot.
44183joules per foot
132.65g x 80cal =10560gramcalories
10560 = 44183.04joules
The mirror equation calculator helps you find the unknown among the object position, image position, and focal length of a mirror.
www.omnicalculator.com
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This article addresses the call of the Psychology of Global Crises conference for linkage of academic work with social issues in three parts: First, examples from conference participants with their mix of bold calls for social transformation and ...
pmc.ncbi.nlm.nih.gov
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Can an array of linearly parabolic mirrors help process optical data from telescopes?

What happens if you put concentrated solar on a peltier tile? If I point the PhotoVoltaic Cells into the mirror, they will generate a higher voltage than when they are pointed up at the sun. If the focal rectangle of the linearly parabolic mirror is partly photovoltaic, it 25% of that concentrated area will be converted to electricity. It would be nice if that amount of energy powered the compressor.
Like, the Peltier Tiles point towards the mirror and charge the ice up to liquid. While the PV are pointed to the sun, that voltage is applied to the Peltier Tiles. Maybe I need to put the Peltier Tiles on a different side of the focal area for nighttime operation I could throw a body warmer in there.
Then, the spit turns around and points the photovoltaic cells at the mirror and the bellows start moving.