Dauntless
100 TW
. . . .Was gettin' at when they blew it up in 'Hitchhikers Guide to the Galaxy.'
If
x² + xy + y³ = 1,
find the value of
y'''
at the point where
x = 1.
So as long as remains 1, as we all know it would;
y=0,
y'= −2,
y''=2,
y'''= (Need I even answer that?)
I mean, bad things happen when THAT comes up. What if the aliens are monitoring this board? I think the real secret is that they needed to cover up all the effort they went to when I was just able to sit here and figure it out. This answer probably had best remain hushhush, at least while there might be some planning commission meeting coming up.
But you can plug in x = 1, y = 0, y' = −2 and y'' = 2 into the equation to find y'''
3y'' + xy''' + 6(y')³ + 18yy'y'' + 3y²y''' = 0
3(2) + y''' + 6(−2)³ + 0 + 0 = 0
6 + y''' − 48 = 0
If
x² + xy + y³ = 1,
find the value of
y'''
at the point where
x = 1.
So as long as remains 1, as we all know it would;
y=0,
y'= −2,
y''=2,
y'''= (Need I even answer that?)
I mean, bad things happen when THAT comes up. What if the aliens are monitoring this board? I think the real secret is that they needed to cover up all the effort they went to when I was just able to sit here and figure it out. This answer probably had best remain hushhush, at least while there might be some planning commission meeting coming up.
But you can plug in x = 1, y = 0, y' = −2 and y'' = 2 into the equation to find y'''
3y'' + xy''' + 6(y')³ + 18yy'y'' + 3y²y''' = 0
3(2) + y''' + 6(−2)³ + 0 + 0 = 0
6 + y''' − 48 = 0
