You mean close to....... No motor will ever achieve no-load rpm when loaded!Hillhater said:Mathematically both calcs are correct but you are both assuming that you can achieve no-load rpms at your target speed.
That aint gonna happen ! ... motors wont achieve max NL rpm under load unless they are hugely overrated ( like X 10 !)
you need to estimate or experiment to establish you motors loaded performance.
Using one of these calculators will be much easier (use mph at 100 rpm in the Gear units pulldown):so for a Kv of 75 .... and 30 mph ...
Motor maximum off load rpm = 48 volts x 75 = 3600 rpm
Wheel rpm at 30mph = (5280 ft /60 mins) / (30 mph x 3.142 x 2 ft) = 422.5 RPM
Reduction ratio required = 3600/422.5 = 8.5
Is that correct ?
Just figure on 80%-85% (Miles suggests using 85%). That will be close enough for gearing. So in the example above:Mathematically both calcs are correct but you are both assuming that you can achieve no-load rpms at your target speed.
That aint gonna happen ! ... motors wont achieve max NL rpm under load unless they are hugely overrated ( like X 10 !)
you need to estimate or experiment to establish you motors loaded performance.
7.7 is at 1:1 so about 400 rpm for 30 mph so at 3,060 rpm you would need a 7.65:1 reduction which is reasonable and makes that motor a good choice (NOTE: If you do a right side drive, to use the gears, through the crank you will probably need about 17:1).10.6
7.7
5.7
the project I want to do with this motor, is an electric motorcycle