Battery question : determining the sweet ratio V/A for range

[arkmundi]

http://endless-sphere.com/forums/viewtopic.php?f=35&t=68887#p1040355

And Joules losses are given by: Pj=R*I^2

The lower current, higher voltage scenario will show less less. But also lower resistance. Meaning optimum gauge wire. And also the more efficient controller, e.g. the one amperage matched. So if running at 30 amps, a 30 amp controller, not one rated higher, which will have higher capacitance fets, which are less efficient though capable of delivering more amps. But yes, the idea is to determine your power requirements, meaning speed, torque and how much weight is being born. Then on that basis, match motor and controller. Then battery matched to that. Also bear in mind that some motors are inherently more efficient. The Falco, for instance, torque per watt.