xyster
10 MW
The PWM current multiplication thread is most engaging and theoretical, but I had a related, practical question to ask:
Knoxie's recently written here (somewhere...
) that his Puma geared hubmotor puts out lots of heat at 72v 35a; that he thinks 60v is a good sweet spot; but he'd like more power and so is going to try and get it without added heat by raising the voltage using a modded 150 volt crystalyte controller.
Because of the PWM Effect, is his approach likely to do anything but increase Amps to the motor, just as would increasing only the controller's current limit?
We know, minus controller losses, that
Volts In X Amps In = Average Volts Out X Amps Out
Let's say Knoxie's cruising uphill at 20 mph with 72v 35a (2520 watts) and the throttle half open such that the motor "sees" 36v 70a. Now let's say Knoxie uses his high voltage controller to double the input the power to 144v 35a (5040 watts). To go the same speed up the same hill, he needs to adjust the controller to 1/4, so that the motor "sees" the same 36v as before, correct?
But if he does that, the motor is seeing 36v 140amps, which is double the amps as before, correct?
In which case it seems the increased voltage bought only more amperage, the heat produced being no different than if he was running a 72 volts 70 amp controller.
But of course he only needs 2520 watts to go 20mph up this hill, so if the throttle is held steady the motor will draw exactly the same 36v 35a as before. So it's not until Knoxie cranks on the throttle that the 144v system will draw double power, accelerating up the hill faster...but when that happens, the heat will be exactly the same with 144v35a going in as at it would be with 72v70a going in. Correct?
If true, because of PWM, doubling the voltage makes no difference in cruising heat losses, and the same difference in full-power WOT heat losses that doubling the current limit does. Which means Knoxie can not make his motor any more efficient at high power by raising the voltage instead of the current limit.
Am I misunderstanding anything?
Knoxie's recently written here (somewhere...
Because of the PWM Effect, is his approach likely to do anything but increase Amps to the motor, just as would increasing only the controller's current limit?
We know, minus controller losses, that
Volts In X Amps In = Average Volts Out X Amps Out
Let's say Knoxie's cruising uphill at 20 mph with 72v 35a (2520 watts) and the throttle half open such that the motor "sees" 36v 70a. Now let's say Knoxie uses his high voltage controller to double the input the power to 144v 35a (5040 watts). To go the same speed up the same hill, he needs to adjust the controller to 1/4, so that the motor "sees" the same 36v as before, correct?
But if he does that, the motor is seeing 36v 140amps, which is double the amps as before, correct?
In which case it seems the increased voltage bought only more amperage, the heat produced being no different than if he was running a 72 volts 70 amp controller.
But of course he only needs 2520 watts to go 20mph up this hill, so if the throttle is held steady the motor will draw exactly the same 36v 35a as before. So it's not until Knoxie cranks on the throttle that the 144v system will draw double power, accelerating up the hill faster...but when that happens, the heat will be exactly the same with 144v35a going in as at it would be with 72v70a going in. Correct?
If true, because of PWM, doubling the voltage makes no difference in cruising heat losses, and the same difference in full-power WOT heat losses that doubling the current limit does. Which means Knoxie can not make his motor any more efficient at high power by raising the voltage instead of the current limit.
Am I misunderstanding anything?