bandaro said:
Oh awesome, thanks a bundle for that, and for your help trying to back-engineer from the pics neil
So if I was to short out the thermistor or whatever it is, the fan would be on permanently? Sounds good to me, so what one is the thermistor thing? Still use a 5k pot to swap the resistor (r33) with, or another one?
There are at least 3 different fan mods for an original Meanwell that I am aware of:
Thermistor
Transistor
One another..no idea what
Others???
I cant comment on what shorting the thermistor will do, it depends what the properties of the thermistor are..and how it is set up..so cant comment on that.
All I know about is the Meanwell transistor mod, that drives it on all the time, but leaves the speed control that the thermistor offers still in place.
Current limiting:
As Red says a 2k pot will do fine across the resistor.
Now this is all assuming that R33 on this design is the same as R33 on a Meanwell...if not, don't say I did not warnyou that this may not work...
So assuming it has the same function as in a Meanwell.
As you reduce the resistance of R33, the current reduces in proportion, so a 25% reduction in the R33 value will result in a 25% reduction in current.
First thing I would do is solder up a couple of leads from the top of the board either side of the resistor, out to your pot, 2k 5k 150k...does not matter at this point...just have it wound up to the highest value
Turn the power on to the supply and Connect up a discharged pack, with an ammeter in series. Monitor the current.
Edit Just had a thought...before you solder the wires either side of the R33...do what I say above and see what current you get out of the un modified supply. now once youknow what the unmodified supply gives out to a discharged pack...continue
Now start winding down the pot.
If R33 is the same as R33 on a proper Meanwell, then at some point the current should start reducing..and you may get some buzzing...thats a Switch mode PSU thing..do not like it but apparently does not harm...though I try to avoid it.
Now...what is the rated output of your supply 350Watt? and what voltage have you setup.....sorry I am typing this and not going to go back up the thread to find out...lazy bastard that I am...
SO;
P=IV
power= current * voltage
therefore
current = power/voltage
work out what current you need, bearing in mind your Supplies rated output power and the voltage you have set.
If you are not clear on putting two resistors in parallel...try google......you will no doubt find a better explanation than I will put here...on the wrong side of a bottle or two of nice red wine.
oh and this may help
http://www.sengpielaudio.com/calculator-paralresist.htm