michaelplogue said:
So, those 'pack' leads are connected in parallel then to the main discharge leads? And should these wires be of a gauge sufficient for the amps put out by the charger, or does it matter?
Yes, to both questions
michaelplogue said:
Just for my own edification, how do these connections function in the overall charging scheme. Don't the leads going to the individual cells handle the charging function?
The current from the charger goes through a circuit that is simply the all the cells in series, and then through the FET that is inserted in series with the negative connection from the charger. During the first part of the charge cycle, the current is maxed out, at whatever the charger can put out. During this "constand current" mode, it becomes harder for the cells to accept this much current, as it "fills", so the cell voltages start to rise at a steady rate. If you had a pack with perfectly matched cells, the they would all rise at the same rate, to the point that the collective sum total (i.e. -- the total pack voltage...) reaches the charger's CC/CV crossover point. Ideally, this will be somewhere around 3.7V x the number of cells in the pack (assuming LiFePO4 cells...), or 44.4V for a 12-cell/36V pack and 59.2V for a 16-cell/48V setup. Once the total voltage reaches that point, the charger will hold it there (the CV mode...) which causes the current to start dropping off. At this point, the cells are about 80-85% full. the current will gradually taper off, down to zero. When it gets under about 100mA, the cells are about as full as they are going to get.
That, or course, is with cells that are perfectly balanced, which is almost never the case. Cell capacities, internal resistances, temperature characteristics, etc., will vary over time, and each cell can change at a different rate. The bottomline is that you almost always end up with cells that hit the cutoff point before the others, and when that happens, the cell voltage starts to rise at a much higher rate. When this happens, it can cause the charger to "see" a pack voltage at the limit, but it might only be one or two cells that are causing the limit to be hit artificially. For these cells, the voltage can and will be a lot higher than the optimum 3.7V point, over 4V even. The cells seem to be able to take this, but it is believed that the long term effect of doing this repeatedly is that cell life will be shortened. In any case, what it also does is to cut the current down quicker than it should, and since all the current has to go through all the cells, the net effect is that many cells will end up not getting a full charge, and this difference between the thower and higher cells can drift apart more and more, over time.
Now, what the BMS does is simply to monitor the voltage of each cell, and if it detects that the cell is at the "magic" cutoff point, it turns on the shunt circuit so that some of the current will start to go through the shunt circuit for that channel instead of causing the cell voltage to start rising. As that first cell gets fuller, the shunt will have to bypass more and more current in order to keep the cell's voltage from quickly rising above the cutoff point (i.e. -- around 3.7V...). The max current the shunt circuit will pass is 1/2A, before it gets overloaded and the cell voltage starts rising again. Just before that happens, the shunt circuit sends a signal to the charger control logic to shut off the FET that is in series with the negative charger power lead. This cuts off
all the charge current, which in turn causes the cell voltage to drop a bit, causing the signal from the shunt circuit to turn back off. That causes the FET to be turned back on, which restores the charge current. What happens is that this cycle repeats. This oscillation, or continuous interruption of the charge current keeps the shunt circuit right at the threshold, just before the circuit overloads. This in turn, keeps the cell voltage right at the optimum cutoff point. When these first cells get full, the shunt circuits still allow up to 1/2A to be available for the next cell in series, so that if it is talking longer to get full, that's okay. Once all the cells are in this full bypass mode, which means the cells are now all finally full, another signal is sent to the charger control logic to shut of the charge current, and keep it off, until the system is reset.
Anyway, to answer your question, the wires going from the BMS board to each of the cell junctions only need to be big enough to handle the shunt bypass current, which is 1/2A.
-- Gary