crossbreak
1 MW
hey Punx0r, what_'s wrong with that example? I know formulas look better if written in LaTex, but that was too much effort for this tiny simple example. i will sum up the formulas again like i did a few pages ago so people can play around with them, and yes i will use LaTex for that, of course.
Some pages back we thought about how to figure out a reasonable nominal speed for a motor. My argumentation: for best efficiency, copper loss equals Iron loss (fact). For best machine exploitation, hysteresis loss shall equal eddy current loss (assumption). Both Fe losses are about equally hard to fight. Eddy current loss by thinner lamination, Hysteresis loss by more sophisticated machine design, better machining/smaller air-gap or more expensive material.

Experience shows that this may be a meaningful. Maybe the 25%/25% are not the whole truth, but at least it determines a nominal rpm. It can simply be calced by dividing Hysteresis torque constant by the Eddy current torque constant. No load currents must be measured quite precisely to get a reasonable number by this. Note the almost 2 times higher rpm of the 40mm SAW compared to the 20mm SAW. How can the 40mm one have so little eddy current loss as it is double the stack compared to the 20mm one?
the cyclone motor simply stays behind it's possibilities. As it's an 8 pole inrunner, it can run a lot faster than the 3500rpm cyclone proposes.
What do you think?
Some pages back we thought about how to figure out a reasonable nominal speed for a motor. My argumentation: for best efficiency, copper loss equals Iron loss (fact). For best machine exploitation, hysteresis loss shall equal eddy current loss (assumption). Both Fe losses are about equally hard to fight. Eddy current loss by thinner lamination, Hysteresis loss by more sophisticated machine design, better machining/smaller air-gap or more expensive material.

Experience shows that this may be a meaningful. Maybe the 25%/25% are not the whole truth, but at least it determines a nominal rpm. It can simply be calced by dividing Hysteresis torque constant by the Eddy current torque constant. No load currents must be measured quite precisely to get a reasonable number by this. Note the almost 2 times higher rpm of the 40mm SAW compared to the 20mm SAW. How can the 40mm one have so little eddy current loss as it is double the stack compared to the 20mm one?
the cyclone motor simply stays behind it's possibilities. As it's an 8 pole inrunner, it can run a lot faster than the 3500rpm cyclone proposes.
What do you think?