Hangdog98
10 W
Hi Nick, yes I re-read my post and even confused myself. Any dumbing down in this explanation is for my benefit, not yours.
OK, steady state etc etc. What I'll attempt to discuss is the comparison of two identical bikes of different mass location configurations travelling around the same constant radius corner at the same speed, same everything. The only variable is the position of the battery pack. Bike #1 is your MTB with the battery pack at the top, bike #2 is your bike again with the battery pack moved to a position under the bottom bracket. The argument enters the realm of the ball on a string moving in a circle - centripetal/centrifugal force. What I am trying to describe is the effect that carrying weight higher on the bike results in less centrifugal force trying to make the bike deviate outwardly from its path around the corner, (usually on its side accompanied by a tumbling rider).
Even though the bike turns the corner because of the tyres, the forces acting upon it are like those of the ball on the string. The bike draws an arc, that arc has a radius being the centre-point of an imaginary circle, that radius is the piece of string. The bike is the ball.
Bike #1 carries a fair amount of mass in a high position when travelling upright. When it is leaned over 45 deg for the turn, that mass moves one hundred centimetres* towards the centre-point of the imaginary circle. The centre of mass of bike #1 is 'A'.
Bike #2 carries a fair amount of mass in a low position when travelling upright. When it is leaned over 45 deg for the turn, that mass moves ten centimetres* toward the centrepoint of the imaginary circle. The centre of mass of bike #2 is 'B'.
A is closer to the centrepoint of the imaginary circle than B is.
A's velocity is therefore less than B's.
The centrifugal force acting on bike #1 is less than that acting on bike #2 because A is slower than B.
The demand on tyre grip and lean angle is less on bike #1 than it is on bike #2
Bike #1 can now go faster than bike #2 and bring the velocity of A to be same as B. Even though bike #1's speed is now higher than bike #2, the centrifugal forces are the same.
OR, the ball on the string becomes elongated on the string and moves some of its mass towards the pivot point and turns the centrifugal/centripetal energy differential into greater speed. Wheeeeeee.
Does that make any sense or did Sir Isaac Newton just roll his eyes at me?
Of course steering dynamics are much more complex than this, but this, I believe, is one way that weight positioning can affect cornering.
(* for example)
OK, steady state etc etc. What I'll attempt to discuss is the comparison of two identical bikes of different mass location configurations travelling around the same constant radius corner at the same speed, same everything. The only variable is the position of the battery pack. Bike #1 is your MTB with the battery pack at the top, bike #2 is your bike again with the battery pack moved to a position under the bottom bracket. The argument enters the realm of the ball on a string moving in a circle - centripetal/centrifugal force. What I am trying to describe is the effect that carrying weight higher on the bike results in less centrifugal force trying to make the bike deviate outwardly from its path around the corner, (usually on its side accompanied by a tumbling rider).
Even though the bike turns the corner because of the tyres, the forces acting upon it are like those of the ball on the string. The bike draws an arc, that arc has a radius being the centre-point of an imaginary circle, that radius is the piece of string. The bike is the ball.
Bike #1 carries a fair amount of mass in a high position when travelling upright. When it is leaned over 45 deg for the turn, that mass moves one hundred centimetres* towards the centre-point of the imaginary circle. The centre of mass of bike #1 is 'A'.
Bike #2 carries a fair amount of mass in a low position when travelling upright. When it is leaned over 45 deg for the turn, that mass moves ten centimetres* toward the centrepoint of the imaginary circle. The centre of mass of bike #2 is 'B'.
A is closer to the centrepoint of the imaginary circle than B is.
A's velocity is therefore less than B's.
The centrifugal force acting on bike #1 is less than that acting on bike #2 because A is slower than B.
The demand on tyre grip and lean angle is less on bike #1 than it is on bike #2
Bike #1 can now go faster than bike #2 and bring the velocity of A to be same as B. Even though bike #1's speed is now higher than bike #2, the centrifugal forces are the same.
OR, the ball on the string becomes elongated on the string and moves some of its mass towards the pivot point and turns the centrifugal/centripetal energy differential into greater speed. Wheeeeeee.
Does that make any sense or did Sir Isaac Newton just roll his eyes at me?

Of course steering dynamics are much more complex than this, but this, I believe, is one way that weight positioning can affect cornering.
(* for example)