First, please tell me if the two statements below are 100% correct:
"Maximum torque is at zero RPM and peak power is at 65% of maximum rpm, around 45-55 rpm (crank rpm). You go uphill fastest if you keep your cadence to 45-55 rpm, you have maximum assistance but that does not equal to having maximum torque. You have maximum torque when you stall."
"Torque peaks around 1500 rpm on electric motors."
So, if the above is true, does that mean the best reduction ratio for a mid-drive is 30:1? So that 50 rpm crank cadence = 1500 rpm motor speed?
Lastly, not to complicate things, but if there is a separate drive chain from the cassette chain, and the drive chain reduction is set to around 3.0 (the motor's sprocket is say 16T and the motor chainring is 48T) does that mean internally that there must be some internal motor gearing that's around 10:1, otherwise for a direct drive motor with zero internal gearing, in the middle of the bike with a chain reduction of 3.0, the rider would have to pedal at 500 rpm for the best torque efficency?
"Maximum torque is at zero RPM and peak power is at 65% of maximum rpm, around 45-55 rpm (crank rpm). You go uphill fastest if you keep your cadence to 45-55 rpm, you have maximum assistance but that does not equal to having maximum torque. You have maximum torque when you stall."
"Torque peaks around 1500 rpm on electric motors."
So, if the above is true, does that mean the best reduction ratio for a mid-drive is 30:1? So that 50 rpm crank cadence = 1500 rpm motor speed?
Lastly, not to complicate things, but if there is a separate drive chain from the cassette chain, and the drive chain reduction is set to around 3.0 (the motor's sprocket is say 16T and the motor chainring is 48T) does that mean internally that there must be some internal motor gearing that's around 10:1, otherwise for a direct drive motor with zero internal gearing, in the middle of the bike with a chain reduction of 3.0, the rider would have to pedal at 500 rpm for the best torque efficency?