Arlo1 said:
because the amps flowing through the motor (phase amps) is what controls the heat but is also what controls the torque.
2x the phase amps = 2x the torque (minus increasing efficiency losses) and also = 2x the heat (plus increasing efficiency losses.)
??? "minus increasing efficiency losses" and "plus increasing efficiency losses"...???
If you re-read this you will understand what I said as in 2x the current is not perfectly 2x the torque it will have a little less then 2x the torque as the losses will increase as well
2x the phase amps = 2x the torque...period, unless you are into saturation where increasing current has diminishing returns up to full saturation where no more torque is created.
2x the phase amps = 4x the heat...period. Copper losses is current squared times resistance. Copper losses also increase with temperature, because resistance increases with temperature, but that's outside of the discussion point.
You got me here but that is some of what I was saying about the losses increasing as the current does.
Who's lazy and ignorant? You've got some nerve posting that stupid video.